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55505561011133 is a prime number
BaseRepresentation
bin11001001111011011001010…
…01111110100001110111101
321021112021112222111201221212
430213231211033310032331
524233400342104324013
6314014522552534205
714456100355032242
oct1447554517641675
9237467488451855
1055505561011133
111675a85a189012
1262854240b1365
1324c81c8a8ac2c
14d9c6aa98d5c9
15663c612d66a8
hex327b653f43bd

55505561011133 has 2 divisors, whose sum is σ = 55505561011134. Its totient is φ = 55505561011132.

The previous prime is 55505561011099. The next prime is 55505561011157. The reversal of 55505561011133 is 33111016550555.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52125324325369 + 3380236685764 = 7219787^2 + 1838542^2 .

It is a cyclic number.

It is not a de Polignac number, because 55505561011133 - 224 = 55505544233917 is a prime.

It is a super-3 number, since 3×555055610111333 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55505561001133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27752780505566 + 27752780505567.

It is an arithmetic number, because the mean of its divisors is an integer number (27752780505567).

Almost surely, 255505561011133 is an apocalyptic number.

It is an amenable number.

55505561011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

55505561011133 is an equidigital number, since it uses as much as digits as its factorization.

55505561011133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168750, while the sum is 41.

Adding to 55505561011133 its reverse (33111016550555), we get a palindrome (88616577561688).

The spelling of 55505561011133 in words is "fifty-five trillion, five hundred five billion, five hundred sixty-one million, eleven thousand, one hundred thirty-three".