Base | Representation |
---|---|
bin | 101000011000111011101… |
… | …0110001011111000110111 |
3 | 201122200100201002101120011 |
4 | 1100301313112023320313 |
5 | 1211422123103112444 |
6 | 15450050135121051 |
7 | 1112024301622156 |
oct | 120616726137067 |
9 | 21580321071504 |
10 | 5551100050999 |
11 | 1850232297668 |
12 | 757a10213187 |
13 | 31360ab4c9b9 |
14 | 15296344d59d |
15 | 995e4590734 |
hex | 50c7758be37 |
5551100050999 has 4 divisors (see below), whose sum is σ = 5551121691360. Its totient is φ = 5551078410640.
The previous prime is 5551100050997. The next prime is 5551100051099. The reversal of 5551100050999 is 9990500011555.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5551100050999 - 21 = 5551100050997 is a prime.
It is a super-2 number, since 2×55511000509992 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5551100050997) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10430734 + ... + 10949995.
It is an arithmetic number, because the mean of its divisors is an integer number (1387780422840).
Almost surely, 25551100050999 is an apocalyptic number.
5551100050999 is a deficient number, since it is larger than the sum of its proper divisors (21640361).
5551100050999 is a wasteful number, since it uses less digits than its factorization.
5551100050999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21640360.
The product of its (nonzero) digits is 455625, while the sum is 49.
The spelling of 5551100050999 in words is "five trillion, five hundred fifty-one billion, one hundred million, fifty thousand, nine hundred ninety-nine".
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