Base | Representation |
---|---|
bin | 101000011000111100000… |
… | …0111110010001101011111 |
3 | 201122200101121112221222121 |
4 | 1100301320013302031133 |
5 | 1211422134420144043 |
6 | 15450051321523411 |
7 | 1112024520264016 |
oct | 120617007621537 |
9 | 21580347487877 |
10 | 5551113053023 |
11 | 185023966823a |
12 | 757a14643567 |
13 | 313610752ac5 |
14 | 152965075a7d |
15 | 995e57acded |
hex | 50c781f235f |
5551113053023 has 2 divisors, whose sum is σ = 5551113053024. Its totient is φ = 5551113053022.
The previous prime is 5551113052951. The next prime is 5551113053047. The reversal of 5551113053023 is 3203503111555.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5551113053023 is a prime.
It is a super-3 number, since 3×55511130530233 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 5551113053023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5551113053623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2775556526511 + 2775556526512.
It is an arithmetic number, because the mean of its divisors is an integer number (2775556526512).
Almost surely, 25551113053023 is an apocalyptic number.
5551113053023 is a deficient number, since it is larger than the sum of its proper divisors (1).
5551113053023 is an equidigital number, since it uses as much as digits as its factorization.
5551113053023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33750, while the sum is 34.
Adding to 5551113053023 its reverse (3203503111555), we get a palindrome (8754616164578).
The spelling of 5551113053023 in words is "five trillion, five hundred fifty-one billion, one hundred thirteen million, fifty-three thousand, twenty-three".
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