Base | Representation |
---|---|
bin | 101000011000111100000… |
… | …0111110010010011010111 |
3 | 201122200101121112222111112 |
4 | 1100301320013302103113 |
5 | 1211422134420202044 |
6 | 15450051321525235 |
7 | 1112024520265064 |
oct | 120617007622327 |
9 | 21580347488445 |
10 | 5551113053399 |
11 | 1850239668551 |
12 | 757a1464381b |
13 | 313610753024 |
14 | 152965075c6b |
15 | 995e57ad09e |
hex | 50c781f24d7 |
5551113053399 has 2 divisors, whose sum is σ = 5551113053400. Its totient is φ = 5551113053398.
The previous prime is 5551113053333. The next prime is 5551113053489. The reversal of 5551113053399 is 9933503111555.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5551113053399 is a prime.
It is a super-3 number, since 3×55511130533993 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5551113053599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2775556526699 + 2775556526700.
It is an arithmetic number, because the mean of its divisors is an integer number (2775556526700).
Almost surely, 25551113053399 is an apocalyptic number.
5551113053399 is a deficient number, since it is larger than the sum of its proper divisors (1).
5551113053399 is an equidigital number, since it uses as much as digits as its factorization.
5551113053399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1366875, while the sum is 50.
The spelling of 5551113053399 in words is "five trillion, five hundred fifty-one billion, one hundred thirteen million, fifty-three thousand, three hundred ninety-nine".
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