Base | Representation |
---|---|
bin | 101000011010111011111… |
… | …0111000001011010000101 |
3 | 201200002110122000122210012 |
4 | 1100311313313001122011 |
5 | 1212004431312013432 |
6 | 15452041151440005 |
7 | 1112236036455332 |
oct | 120656767013205 |
9 | 21602418018705 |
10 | 5555403626117 |
11 | 1852040577314 |
12 | 758811526005 |
13 | 313b45621557 |
14 | 152c50c27989 |
15 | 997972cdcb2 |
hex | 50d77dc1685 |
5555403626117 has 2 divisors, whose sum is σ = 5555403626118. Its totient is φ = 5555403626116.
The previous prime is 5555403626111. The next prime is 5555403626137. The reversal of 5555403626117 is 7116263045555.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4946669740321 + 608733885796 = 2224111^2 + 780214^2 .
It is a cyclic number.
It is not a de Polignac number, because 5555403626117 - 236 = 5486684149381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5555403626111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2777701813058 + 2777701813059.
It is an arithmetic number, because the mean of its divisors is an integer number (2777701813059).
Almost surely, 25555403626117 is an apocalyptic number.
It is an amenable number.
5555403626117 is a deficient number, since it is larger than the sum of its proper divisors (1).
5555403626117 is an equidigital number, since it uses as much as digits as its factorization.
5555403626117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780000, while the sum is 50.
The spelling of 5555403626117 in words is "five trillion, five hundred fifty-five billion, four hundred three million, six hundred twenty-six thousand, one hundred seventeen".
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