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5555498402893 is a prime number
BaseRepresentation
bin101000011010111110110…
…0000100100010001001101
3201200002201020100211002011
41100311331200210101031
51212010130042343033
615452054415101221
71112241300164425
oct120657540442115
921602636324064
105555498402893
11185208a02052a
12758839211811
13313b5c15679a
14152c5d659485
15997a07a0ccd
hex50d7d82444d

5555498402893 has 2 divisors, whose sum is σ = 5555498402894. Its totient is φ = 5555498402892.

The previous prime is 5555498402873. The next prime is 5555498402903. The reversal of 5555498402893 is 3982048945555.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5540572160964 + 14926241929 = 2353842^2 + 122173^2 .

It is a cyclic number.

It is not a de Polignac number, because 5555498402893 - 241 = 3356475147341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5555498402833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2777749201446 + 2777749201447.

It is an arithmetic number, because the mean of its divisors is an integer number (2777749201447).

Almost surely, 25555498402893 is an apocalyptic number.

It is an amenable number.

5555498402893 is a deficient number, since it is larger than the sum of its proper divisors (1).

5555498402893 is an equidigital number, since it uses as much as digits as its factorization.

5555498402893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040000, while the sum is 67.

The spelling of 5555498402893 in words is "five trillion, five hundred fifty-five billion, four hundred ninety-eight million, four hundred two thousand, eight hundred ninety-three".