Base | Representation |
---|---|
bin | 110011101111010101… |
… | …100000100010100011 |
3 | 12022101201112102201111 |
4 | 303233111200202203 |
5 | 1402234040003413 |
6 | 41304400244151 |
7 | 4004463466303 |
oct | 635725404243 |
9 | 168351472644 |
10 | 55555000483 |
11 | 21619393144 |
12 | a925310657 |
13 | 531489cb68 |
14 | 29903c3603 |
15 | 16a23cad3d |
hex | cef5608a3 |
55555000483 has 2 divisors, whose sum is σ = 55555000484. Its totient is φ = 55555000482.
The previous prime is 55555000481. The next prime is 55555000531. The reversal of 55555000483 is 38400055555.
55555000483 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55555000483 - 21 = 55555000481 is a prime.
It is a super-3 number, since 3×555550004833 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 55555000481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (55555000481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27777500241 + 27777500242.
It is an arithmetic number, because the mean of its divisors is an integer number (27777500242).
Almost surely, 255555000483 is an apocalyptic number.
55555000483 is a deficient number, since it is larger than the sum of its proper divisors (1).
55555000483 is an equidigital number, since it uses as much as digits as its factorization.
55555000483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 300000, while the sum is 40.
The spelling of 55555000483 in words is "fifty-five billion, five hundred fifty-five million, four hundred eighty-three", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.107 sec. • engine limits •