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556428354773 is a prime number
BaseRepresentation
bin10000001100011011011…
…01101110010011010101
31222012020110010010211012
420012031231232103111
533104031124323043
61103341502422005
755125545656244
oct10061555562325
91865213103735
10556428354773
111a4a86333645
128ba0a891905
1340617945005
141cd075c895b
15e719a25a18
hex818db6e4d5

556428354773 has 2 divisors, whose sum is σ = 556428354774. Its totient is φ = 556428354772.

The previous prime is 556428354709. The next prime is 556428354809. The reversal of 556428354773 is 377453824655.

556428354773 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 327708161764 + 228720193009 = 572458^2 + 478247^2 .

It is a cyclic number.

It is not a de Polignac number, because 556428354773 - 26 = 556428354709 is a prime.

It is a super-2 number, since 2×5564283547732 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (556428354973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278214177386 + 278214177387.

It is an arithmetic number, because the mean of its divisors is an integer number (278214177387).

Almost surely, 2556428354773 is an apocalyptic number.

It is an amenable number.

556428354773 is a deficient number, since it is larger than the sum of its proper divisors (1).

556428354773 is an equidigital number, since it uses as much as digits as its factorization.

556428354773 is an evil number, because the sum of its binary digits is even.

The product of its digits is 84672000, while the sum is 59.

The spelling of 556428354773 in words is "five hundred fifty-six billion, four hundred twenty-eight million, three hundred fifty-four thousand, seven hundred seventy-three".