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55715025341 is a prime number
BaseRepresentation
bin110011111000110111…
…111101000110111101
312022210212122112120002
4303320313331012331
51403101021302331
641332314204045
74011445621133
oct637067750675
9168725575502
1055715025341
11216a0752198
12a96aa23625
13533ba9ba21
1429a775b753
1516b148a9cb
hexcf8dfd1bd

55715025341 has 2 divisors, whose sum is σ = 55715025342. Its totient is φ = 55715025340.

The previous prime is 55715025277. The next prime is 55715025409. The reversal of 55715025341 is 14352051755.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 52978689241 + 2736336100 = 230171^2 + 52310^2 .

It is a cyclic number.

It is not a de Polignac number, because 55715025341 - 26 = 55715025277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 55715025295 and 55715025304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (55745025341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27857512670 + 27857512671.

It is an arithmetic number, because the mean of its divisors is an integer number (27857512671).

Almost surely, 255715025341 is an apocalyptic number.

It is an amenable number.

55715025341 is a deficient number, since it is larger than the sum of its proper divisors (1).

55715025341 is an equidigital number, since it uses as much as digits as its factorization.

55715025341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 105000, while the sum is 38.

The spelling of 55715025341 in words is "fifty-five billion, seven hundred fifteen million, twenty-five thousand, three hundred forty-one".