Base | Representation |
---|---|
bin | 10000001110001011011… |
… | …10101111111000100101 |
3 | 1222021122221111120001222 |
4 | 20013011232233320211 |
5 | 33112442221204433 |
6 | 1104015033430125 |
7 | 55161050040563 |
oct | 10070556577045 |
9 | 1867587446058 |
10 | 557368147493 |
11 | 1a5418874843 |
12 | 9003156b345 |
13 | 40737561a91 |
14 | 1cd96342a33 |
15 | e7722b2b98 |
hex | 81c5bafe25 |
557368147493 has 2 divisors, whose sum is σ = 557368147494. Its totient is φ = 557368147492.
The previous prime is 557368147481. The next prime is 557368147499. The reversal of 557368147493 is 394741863755.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 285533128609 + 271835018884 = 534353^2 + 521378^2 .
It is a cyclic number.
It is not a de Polignac number, because 557368147493 - 222 = 557363953189 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (557368147499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 278684073746 + 278684073747.
It is an arithmetic number, because the mean of its divisors is an integer number (278684073747).
Almost surely, 2557368147493 is an apocalyptic number.
It is an amenable number.
557368147493 is a deficient number, since it is larger than the sum of its proper divisors (1).
557368147493 is an equidigital number, since it uses as much as digits as its factorization.
557368147493 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 76204800, while the sum is 62.
The spelling of 557368147493 in words is "five hundred fifty-seven billion, three hundred sixty-eight million, one hundred forty-seven thousand, four hundred ninety-three".
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