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55775175414353 = 232425007626711
BaseRepresentation
bin11001010111010001010111…
…00001001001001001010001
321022111001110212120111222122
430223220223201021021101
524302310024401224403
6314342432321144025
714514423561453113
oct1453505341111121
9238431425514878
1055775175414353
111685413451375a
12630972948b015
132517765686c75
14dab7663913b3
1566ac910a0838
hex32ba2b849251

55775175414353 has 4 divisors (see below), whose sum is σ = 58200183041088. Its totient is φ = 53350167787620.

The previous prime is 55775175414317. The next prime is 55775175414373. The reversal of 55775175414353 is 35341457157755.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55775175414353 - 28 = 55775175414097 is a prime.

It is a super-2 number, since 2×557751754143532 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55775175414373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1212503813333 + ... + 1212503813378.

It is an arithmetic number, because the mean of its divisors is an integer number (14550045760272).

Almost surely, 255775175414353 is an apocalyptic number.

It is an amenable number.

55775175414353 is a deficient number, since it is larger than the sum of its proper divisors (2425007626735).

55775175414353 is a wasteful number, since it uses less digits than its factorization.

55775175414353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2425007626734.

The product of its digits is 154350000, while the sum is 62.

The spelling of 55775175414353 in words is "fifty-five trillion, seven hundred seventy-five billion, one hundred seventy-five million, four hundred fourteen thousand, three hundred fifty-three".

Divisors: 1 23 2425007626711 55775175414353