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55778337503081 is a prime number
BaseRepresentation
bin11001010111010111001111…
…11111100011011101101001
321022111100122020121021020222
430223223213333203131221
524302333013400044311
6314344114155455425
714514565125664514
oct1453534777433551
9238440566537228
1055778337503081
1116855507422826
12630a270457575
132517b4a81089b
14dab98630bd7b
1566adc89b0adb
hex32bae7fe3769

55778337503081 has 2 divisors, whose sum is σ = 55778337503082. Its totient is φ = 55778337503080.

The previous prime is 55778337503027. The next prime is 55778337503143. The reversal of 55778337503081 is 18030573387755.

It is an a-pointer prime, because the next prime (55778337503143) can be obtained adding 55778337503081 to its sum of digits (62).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31882860613081 + 23895476890000 = 5646491^2 + 4888300^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55778337503081 is a prime.

It is a super-2 number, since 2×557783375030812 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (55778337506081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27889168751540 + 27889168751541.

It is an arithmetic number, because the mean of its divisors is an integer number (27889168751541).

Almost surely, 255778337503081 is an apocalyptic number.

It is an amenable number.

55778337503081 is a deficient number, since it is larger than the sum of its proper divisors (1).

55778337503081 is an equidigital number, since it uses as much as digits as its factorization.

55778337503081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 74088000, while the sum is 62.

The spelling of 55778337503081 in words is "fifty-five trillion, seven hundred seventy-eight billion, three hundred thirty-seven million, five hundred three thousand, eighty-one".