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55906099724113 is a prime number
BaseRepresentation
bin11001011011000101001110…
…01101101111111101010001
321022221120102012202120020021
430231202213031233331101
524311431143012132423
6314522524015343441
714530040160645112
oct1455424715577521
9238846365676207
1055906099724113
11168a4709909451
12632ab87821b81
132526bcbbb7142
14db3c26504209
1566e3a514395d
hex32d8a736ff51

55906099724113 has 2 divisors, whose sum is σ = 55906099724114. Its totient is φ = 55906099724112.

The previous prime is 55906099724093. The next prime is 55906099724129. The reversal of 55906099724113 is 31142799060955.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 48267575615169 + 7638524108944 = 6947487^2 + 2763788^2 .

It is a cyclic number.

It is not a de Polignac number, because 55906099724113 - 25 = 55906099724081 is a prime.

It is not a weakly prime, because it can be changed into another prime (55906099724183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27953049862056 + 27953049862057.

It is an arithmetic number, because the mean of its divisors is an integer number (27953049862057).

Almost surely, 255906099724113 is an apocalyptic number.

It is an amenable number.

55906099724113 is a deficient number, since it is larger than the sum of its proper divisors (1).

55906099724113 is an equidigital number, since it uses as much as digits as its factorization.

55906099724113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18370800, while the sum is 61.

The spelling of 55906099724113 in words is "fifty-five trillion, nine hundred six billion, ninety-nine million, seven hundred twenty-four thousand, one hundred thirteen".