Base | Representation |
---|---|
bin | 1010011010100000… |
… | …00100111011101001 |
3 | 112102122111121210010 |
4 | 11031100010323221 |
5 | 42422300334213 |
6 | 2322443042133 |
7 | 255356643345 |
oct | 51520047351 |
9 | 15378447703 |
10 | 5591027433 |
11 | 2409a97732 |
12 | 1100510349 |
13 | 6b1435474 |
14 | 3b0790625 |
15 | 22aca0ac3 |
hex | 14d404ee9 |
5591027433 has 8 divisors (see below), whose sum is σ = 7455732768. Its totient is φ = 3726836864.
The previous prime is 5591027411. The next prime is 5591027461. The reversal of 5591027433 is 3347201955.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5591027433 - 210 = 5591026409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5591027391 and 5591027400.
It is not an unprimeable number, because it can be changed into a prime (5591027483) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102591 + ... + 147332.
It is an arithmetic number, because the mean of its divisors is an integer number (931966596).
Almost surely, 25591027433 is an apocalyptic number.
It is an amenable number.
5591027433 is a deficient number, since it is larger than the sum of its proper divisors (1864705335).
5591027433 is a wasteful number, since it uses less digits than its factorization.
5591027433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 257383.
The product of its (nonzero) digits is 113400, while the sum is 39.
The square root of 5591027433 is about 74773.1732174046. The cubic root of 5591027433 is about 1774.8590705275.
The spelling of 5591027433 in words is "five billion, five hundred ninety-one million, twenty-seven thousand, four hundred thirty-three".
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