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55913003 is a prime number
BaseRepresentation
bin1101010101001…
…0101000101011
310220012200012222
43111102220223
5103303204003
65314224255
71246152446
oct325225053
9126180188
1055913003
112961a2a3
121688508b
13b778923
1475d665d
154d96c38
hex3552a2b

55913003 has 2 divisors, whose sum is σ = 55913004. Its totient is φ = 55913002.

The previous prime is 55912999. The next prime is 55913009. The reversal of 55913003 is 30031955.

55913003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 55913003 - 22 = 55912999 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (55913009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27956501 + 27956502.

It is an arithmetic number, because the mean of its divisors is an integer number (27956502).

Almost surely, 255913003 is an apocalyptic number.

55913003 is a deficient number, since it is larger than the sum of its proper divisors (1).

55913003 is an equidigital number, since it uses as much as digits as its factorization.

55913003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2025, while the sum is 26.

The square root of 55913003 is about 7477.4997826814. The cubic root of 55913003 is about 382.3880156890.

Adding to 55913003 its reverse (30031955), we get a palindrome (85944958).

The spelling of 55913003 in words is "fifty-five million, nine hundred thirteen thousand, three".