Base | Representation |
---|---|
bin | 110100000110010101… |
… | …111110111010110011 |
3 | 12100101121212021201121 |
4 | 310012111332322303 |
5 | 1404031344012013 |
6 | 41410545443111 |
7 | 4020161443015 |
oct | 640625767263 |
9 | 170347767647 |
10 | 55941000883 |
11 | 217a7266a39 |
12 | aa12640497 |
13 | 537684c271 |
14 | 29c97821b5 |
15 | 16c622658d |
hex | d0657eeb3 |
55941000883 has 2 divisors, whose sum is σ = 55941000884. Its totient is φ = 55941000882.
The previous prime is 55941000881. The next prime is 55941000919. The reversal of 55941000883 is 38800014955.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 55941000883 - 21 = 55941000881 is a prime.
Together with 55941000881, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (55941000881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27970500441 + 27970500442.
It is an arithmetic number, because the mean of its divisors is an integer number (27970500442).
Almost surely, 255941000883 is an apocalyptic number.
55941000883 is a deficient number, since it is larger than the sum of its proper divisors (1).
55941000883 is an equidigital number, since it uses as much as digits as its factorization.
55941000883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 43.
The spelling of 55941000883 in words is "fifty-five billion, nine hundred forty-one million, eight hundred eighty-three", and thus it is an aban number.
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