Base | Representation |
---|---|
bin | 11001011100010011001100… |
… | …00010101011001100101011 |
3 | 21100002120110020200102011221 |
4 | 30232021212002223030223 |
5 | 24313122403212144310 |
6 | 314554045224202511 |
7 | 14533051335134002 |
oct | 1456114602531453 |
9 | 240076406612157 |
10 | 55947955974955 |
11 | 169104386511a0 |
12 | 6337109309437 |
13 | 252ab3c6c3085 |
14 | db5c7742bc39 |
15 | 670504a95ada |
hex | 32e2660ab32b |
55947955974955 has 16 divisors (see below), whose sum is σ = 73505368368864. Its totient is φ = 40542529294080.
The previous prime is 55947955974947. The next prime is 55947955975063.
55947955974955 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55947955974955 - 23 = 55947955974947 is a prime.
It is a super-3 number, since 3×559479559749553 (a number of 42 digits) contains 333 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1836150042 + ... + 1836180511.
It is an arithmetic number, because the mean of its divisors is an integer number (4594085523054).
Almost surely, 255947955974955 is an apocalyptic number.
55947955974955 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55947955974955 is a deficient number, since it is larger than the sum of its proper divisors (17557412393909).
55947955974955 is a wasteful number, since it uses less digits than its factorization.
55947955974955 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3672330846.
The product of its digits is 80372250000, while the sum is 88.
The spelling of 55947955974955 in words is "fifty-five trillion, nine hundred forty-seven billion, nine hundred fifty-five million, nine hundred seventy-four thousand, nine hundred fifty-five".
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