Base | Representation |
---|---|
bin | 100001011000001… |
… | …111111111111101 |
3 | 1110000202012121021 |
4 | 201120033333331 |
5 | 2121330130432 |
6 | 131322504141 |
7 | 16606651660 |
oct | 4130177775 |
9 | 1400665537 |
10 | 560005117 |
11 | 268121151 |
12 | 137665051 |
13 | 8c034499 |
14 | 545356d7 |
15 | 3426c697 |
hex | 2160fffd |
560005117 has 4 divisors (see below), whose sum is σ = 640005856. Its totient is φ = 480004380.
The previous prime is 560005087. The next prime is 560005157. The reversal of 560005117 is 711500065.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-560005117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 560005091 and 560005100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (560005157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40000359 + ... + 40000372.
It is an arithmetic number, because the mean of its divisors is an integer number (160001464).
Almost surely, 2560005117 is an apocalyptic number.
It is an amenable number.
560005117 is a deficient number, since it is larger than the sum of its proper divisors (80000739).
560005117 is an equidigital number, since it uses as much as digits as its factorization.
560005117 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80000738.
The product of its (nonzero) digits is 1050, while the sum is 25.
The square root of 560005117 is about 23664.4272485095. The cubic root of 560005117 is about 824.2595705037.
The spelling of 560005117 in words is "five hundred sixty million, five thousand, one hundred seventeen".
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