Base | Representation |
---|---|
bin | 11001011110000110110001… |
… | …00000110100001111111101 |
3 | 21100022111121121210100120210 |
4 | 30233003120200310033331 |
5 | 24320131443020133432 |
6 | 315042350324103033 |
7 | 14540406106622451 |
oct | 1457033040641775 |
9 | 240274547710523 |
10 | 56010006021117 |
11 | 1693478a248285 |
12 | 6347145834a79 |
13 | 253394aa9aa15 |
14 | db8c82286661 |
15 | 671e372948cc |
hex | 32f0d88343fd |
56010006021117 has 16 divisors (see below), whose sum is σ = 78610706136000. Its totient is φ = 35374663528704.
The previous prime is 56010006021077. The next prime is 56010006021119. The reversal of 56010006021117 is 71112060001065.
It is not a de Polignac number, because 56010006021117 - 238 = 55735128114173 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56010006021119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37191109 + ... + 38667797.
It is an arithmetic number, because the mean of its divisors is an integer number (4913169133500).
Almost surely, 256010006021117 is an apocalyptic number.
56010006021117 is a gapful number since it is divisible by the number (57) formed by its first and last digit.
It is an amenable number.
56010006021117 is a deficient number, since it is larger than the sum of its proper divisors (22600700114883).
56010006021117 is a wasteful number, since it uses less digits than its factorization.
56010006021117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2142140.
The product of its (nonzero) digits is 2520, while the sum is 30.
The spelling of 56010006021117 in words is "fifty-six trillion, ten billion, six million, twenty-one thousand, one hundred seventeen".
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