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5601314993 is a prime number
BaseRepresentation
bin1010011011101110…
…10100100010110001
3112110100212021122212
411031313110202301
542432414034433
62323451341505
7255543251261
oct51567244261
915410767585
105601314993
11241488394a
121103a51895
136b35c7b91
143b1cab7a1
1522bb33d48
hex14ddd48b1

5601314993 has 2 divisors, whose sum is σ = 5601314994. Its totient is φ = 5601314992.

The previous prime is 5601314933. The next prime is 5601315001. The reversal of 5601314993 is 3994131065.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3894633649 + 1706681344 = 62407^2 + 41312^2 .

It is a cyclic number.

It is not a de Polignac number, because 5601314993 - 28 = 5601314737 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5601314993.

It is not a weakly prime, because it can be changed into another prime (5601314903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2800657496 + 2800657497.

It is an arithmetic number, because the mean of its divisors is an integer number (2800657497).

Almost surely, 25601314993 is an apocalyptic number.

It is an amenable number.

5601314993 is a deficient number, since it is larger than the sum of its proper divisors (1).

5601314993 is an equidigital number, since it uses as much as digits as its factorization.

5601314993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 87480, while the sum is 41.

The square root of 5601314993 is about 74841.9333863042. The cubic root of 5601314993 is about 1775.9469911242.

The spelling of 5601314993 in words is "five billion, six hundred one million, three hundred fourteen thousand, nine hundred ninety-three".