Base | Representation |
---|---|
bin | 11001011111101101010011… |
… | …10000011001011110101111 |
3 | 21100111202201011022201200121 |
4 | 30233312221300121132233 |
5 | 24322032213333321341 |
6 | 315123533051305411 |
7 | 14544365233202353 |
oct | 1457665160313657 |
9 | 240452634281617 |
10 | 56065056151471 |
11 | 16956069647a84 |
12 | 6355949a4b267 |
13 | 2538bb1b9bb53 |
14 | dbb7c55a7463 |
15 | 6735aa1944d1 |
hex | 32fda9c197af |
56065056151471 has 2 divisors, whose sum is σ = 56065056151472. Its totient is φ = 56065056151470.
The previous prime is 56065056151457. The next prime is 56065056151519. The reversal of 56065056151471 is 17415165056065.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56065056151471 - 237 = 55927617197999 is a prime.
It is a super-3 number, since 3×560650561514713 (a number of 42 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56065056151441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28032528075735 + 28032528075736.
It is an arithmetic number, because the mean of its divisors is an integer number (28032528075736).
Almost surely, 256065056151471 is an apocalyptic number.
56065056151471 is a deficient number, since it is larger than the sum of its proper divisors (1).
56065056151471 is an equidigital number, since it uses as much as digits as its factorization.
56065056151471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780000, while the sum is 52.
The spelling of 56065056151471 in words is "fifty-six trillion, sixty-five billion, fifty-six million, one hundred fifty-one thousand, four hundred seventy-one".
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