Base | Representation |
---|---|
bin | 101000110100011101010… |
… | …1100100110101111010001 |
3 | 201212022221022202120211001 |
4 | 1101220322230212233101 |
5 | 1213404203241410423 |
6 | 15533143522422001 |
7 | 1116216166456153 |
oct | 121507254465721 |
9 | 21768838676731 |
10 | 5610212060113 |
11 | 18733064a4a61 |
12 | 767368801901 |
13 | 31906b62969b |
14 | 15576ddd0ad3 |
15 | 9ae03d89cad |
hex | 51a3ab26bd1 |
5610212060113 has 2 divisors, whose sum is σ = 5610212060114. Its totient is φ = 5610212060112.
The previous prime is 5610212060051. The next prime is 5610212060137. The reversal of 5610212060113 is 3110602120165.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5235095009089 + 375117051024 = 2288033^2 + 612468^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5610212060113 is a prime.
It is not a weakly prime, because it can be changed into another prime (5610212060153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2805106030056 + 2805106030057.
It is an arithmetic number, because the mean of its divisors is an integer number (2805106030057).
Almost surely, 25610212060113 is an apocalyptic number.
It is an amenable number.
5610212060113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5610212060113 is an equidigital number, since it uses as much as digits as its factorization.
5610212060113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 28.
Adding to 5610212060113 its reverse (3110602120165), we get a palindrome (8720814180278).
The spelling of 5610212060113 in words is "five trillion, six hundred ten billion, two hundred twelve million, sixty thousand, one hundred thirteen".
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