5611341440113 has 2 divisors, whose sum is σ = 5611341440114. Its totient is φ = 5611341440112.

The previous prime is 5611341440099. The next prime is 5611341440137. The reversal of 5611341440113 is 3110441431165.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3005531920609 + 2605809519504 = 1733647^2 + 1614252^2 .

It is a cyclic number.

It is not a de Polignac number, because 5611341440113 - 2¹³ = 5611341431921 is a prime.

It is not a weakly prime, because it can be changed into another prime (5611341440143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2805670720056 + 2805670720057.

It is an arithmetic number, because the mean of its divisors is an integer number (2805670720057).

Almost surely, 2^{5611341440113} is an apocalyptic number.

It is an amenable number.

5611341440113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5611341440113 is an equidigital number, since it uses as much as digits as its factorization.

5611341440113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 34.

Adding to 5611341440113 its reverse (3110441431165), we get a palindrome (8721782871278).

The spelling of 5611341440113 in words is "five trillion, six hundred eleven billion, three hundred forty-one million, four hundred forty thousand, one hundred thirteen".