5611341440137 has 2 divisors, whose sum is σ = 5611341440138. Its totient is φ = 5611341440136.

The previous prime is 5611341440113. The next prime is 5611341440143. The reversal of 5611341440137 is 7310441431165.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3273436221696 + 2337905218441 = 1809264^2 + 1529021^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5611341440137 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5611341440137.

It is not a weakly prime, because it can be changed into another prime (5611341440167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2805670720068 + 2805670720069.

It is an arithmetic number, because the mean of its divisors is an integer number (2805670720069).

Almost surely, 2^{5611341440137} is an apocalyptic number.

It is an amenable number.

5611341440137 is a deficient number, since it is larger than the sum of its proper divisors (1).

5611341440137 is an equidigital number, since it uses as much as digits as its factorization.

5611341440137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 40.

The spelling of 5611341440137 in words is "five trillion, six hundred eleven billion, three hundred forty-one million, four hundred forty thousand, one hundred thirty-seven".