Base | Representation |
---|---|
bin | 110100010001000010… |
… | …010110011001111111 |
3 | 12100212010102212222001 |
4 | 310101002112121333 |
5 | 1404413310403313 |
6 | 41440435003131 |
7 | 4024500362656 |
oct | 642102263177 |
9 | 170763385861 |
10 | 56120403583 |
11 | 21889560932 |
12 | aa627394a7 |
13 | 53a4a742ca |
14 | 2a0552219d |
15 | 16d6d62add |
hex | d1109667f |
56120403583 has 2 divisors, whose sum is σ = 56120403584. Its totient is φ = 56120403582.
The previous prime is 56120403551. The next prime is 56120403589. The reversal of 56120403583 is 38530402165.
56120403583 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 56120403583 - 25 = 56120403551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56120403589) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28060201791 + 28060201792.
It is an arithmetic number, because the mean of its divisors is an integer number (28060201792).
Almost surely, 256120403583 is an apocalyptic number.
56120403583 is a deficient number, since it is larger than the sum of its proper divisors (1).
56120403583 is an equidigital number, since it uses as much as digits as its factorization.
56120403583 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 56120403583 in words is "fifty-six billion, one hundred twenty million, four hundred three thousand, five hundred eighty-three".
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