Base | Representation |
---|---|
bin | 110100010001101011… |
… | …101011001010010111 |
3 | 12100212212211020221022 |
4 | 310101223223022113 |
5 | 1404424044032003 |
6 | 41441503111355 |
7 | 4024661431556 |
oct | 642153531227 |
9 | 170785736838 |
10 | 56131236503 |
11 | 2189468a861 |
12 | aa662a255b |
13 | 53a7098014 |
14 | 2a06b41d9d |
15 | 16d7ca2738 |
hex | d11aeb297 |
56131236503 has 2 divisors, whose sum is σ = 56131236504. Its totient is φ = 56131236502.
The previous prime is 56131236487. The next prime is 56131236523. The reversal of 56131236503 is 30563213165.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56131236503 - 24 = 56131236487 is a prime.
It is a super-2 number, since 2×561312365032 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56131236523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28065618251 + 28065618252.
It is an arithmetic number, because the mean of its divisors is an integer number (28065618252).
Almost surely, 256131236503 is an apocalyptic number.
56131236503 is a deficient number, since it is larger than the sum of its proper divisors (1).
56131236503 is an equidigital number, since it uses as much as digits as its factorization.
56131236503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48600, while the sum is 35.
Adding to 56131236503 its reverse (30563213165), we get a palindrome (86694449668).
The spelling of 56131236503 in words is "fifty-six billion, one hundred thirty-one million, two hundred thirty-six thousand, five hundred three".
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