Base | Representation |
---|---|
bin | 110100010001110000… |
… | …111101101100000111 |
3 | 12100212222102201000011 |
4 | 310101300331230013 |
5 | 1404424422414421 |
6 | 41441552531051 |
7 | 4025006265265 |
oct | 642160755407 |
9 | 170788381004 |
10 | 56132623111 |
11 | 21895447614 |
12 | aa66850a87 |
13 | 53a74621b6 |
14 | 2a06dc3435 |
15 | 16d7e784e1 |
hex | d11c3db07 |
56132623111 has 2 divisors, whose sum is σ = 56132623112. Its totient is φ = 56132623110.
The previous prime is 56132623093. The next prime is 56132623171. The reversal of 56132623111 is 11132623165.
56132623111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56132623111 - 29 = 56132622599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56132623171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28066311555 + 28066311556.
It is an arithmetic number, because the mean of its divisors is an integer number (28066311556).
Almost surely, 256132623111 is an apocalyptic number.
56132623111 is a deficient number, since it is larger than the sum of its proper divisors (1).
56132623111 is an equidigital number, since it uses as much as digits as its factorization.
56132623111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 31.
The spelling of 56132623111 in words is "fifty-six billion, one hundred thirty-two million, six hundred twenty-three thousand, one hundred eleven".
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