Base | Representation |
---|---|
bin | 11001100001101100000011… |
… | …00000110011010110000001 |
3 | 21100202021100021200022010212 |
4 | 30300312001200303112001 |
5 | 24324141042203414301 |
6 | 315215105041003505 |
7 | 14552324362204064 |
oct | 1460660140632601 |
9 | 240667307608125 |
10 | 56133100451201 |
11 | 16981a068aa534 |
12 | 6366b79923595 |
13 | 25424370acab7 |
14 | dc0bdc5768db |
15 | 67523dc434bb |
hex | 330d81833581 |
56133100451201 has 2 divisors, whose sum is σ = 56133100451202. Its totient is φ = 56133100451200.
The previous prime is 56133100451119. The next prime is 56133100451243. The reversal of 56133100451201 is 10215400133165.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 43749281976976 + 12383818474225 = 6614324^2 + 3519065^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56133100451201 is a prime.
It is not a weakly prime, because it can be changed into another prime (56133109451201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28066550225600 + 28066550225601.
It is an arithmetic number, because the mean of its divisors is an integer number (28066550225601).
Almost surely, 256133100451201 is an apocalyptic number.
It is an amenable number.
56133100451201 is a deficient number, since it is larger than the sum of its proper divisors (1).
56133100451201 is an equidigital number, since it uses as much as digits as its factorization.
56133100451201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 56133100451201 its reverse (10215400133165), we get a palindrome (66348500584366).
The spelling of 56133100451201 in words is "fifty-six trillion, one hundred thirty-three billion, one hundred million, four hundred fifty-one thousand, two hundred one".
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