Base | Representation |
---|---|
bin | 11001100001101100000011… |
… | …00000110011010110101011 |
3 | 21100202021100021200022012102 |
4 | 30300312001200303112223 |
5 | 24324141042203414433 |
6 | 315215105041004015 |
7 | 14552324362204154 |
oct | 1460660140632653 |
9 | 240667307608172 |
10 | 56133100451243 |
11 | 16981a068aa572 |
12 | 6366b7992360b |
13 | 25424370acb1a |
14 | dc0bdc57692b |
15 | 67523dc434e8 |
hex | 330d818335ab |
56133100451243 has 2 divisors, whose sum is σ = 56133100451244. Its totient is φ = 56133100451242.
The previous prime is 56133100451201. The next prime is 56133100451249. The reversal of 56133100451243 is 34215400133165.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 56133100451243 - 228 = 56132832015787 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 56133100451197 and 56133100451206.
It is not a weakly prime, because it can be changed into another prime (56133100451249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28066550225621 + 28066550225622.
It is an arithmetic number, because the mean of its divisors is an integer number (28066550225622).
Almost surely, 256133100451243 is an apocalyptic number.
56133100451243 is a deficient number, since it is larger than the sum of its proper divisors (1).
56133100451243 is an equidigital number, since it uses as much as digits as its factorization.
56133100451243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 56133100451243 in words is "fifty-six trillion, one hundred thirty-three billion, one hundred million, four hundred fifty-one thousand, two hundred forty-three".
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