Base | Representation |
---|---|
bin | 11001100010010011110001… |
… | …10110111110111011001111 |
3 | 21100211022101210012002201101 |
4 | 30301021320312332323033 |
5 | 24330013233101413333 |
6 | 315232553345323531 |
7 | 14554011061245361 |
oct | 1461117066767317 |
9 | 240738353162641 |
10 | 56154430107343 |
11 | 1698aa61941927 |
12 | 636b1310365a7 |
13 | 25444560a6cc9 |
14 | dc1c6329cd31 |
15 | 675a8b5ab67d |
hex | 331278dbeecf |
56154430107343 has 8 divisors (see below), whose sum is σ = 56167047334160. Its totient is φ = 56141813370240.
The previous prime is 56154430107331. The next prime is 56154430107367. The reversal of 56154430107343 is 34370103445165.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 56154430107343 - 25 = 56154430107311 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 56154430107293 and 56154430107302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56154430107943) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 322026688 + ... + 322201018.
It is an arithmetic number, because the mean of its divisors is an integer number (7020880916770).
Almost surely, 256154430107343 is an apocalyptic number.
56154430107343 is a deficient number, since it is larger than the sum of its proper divisors (12617226817).
56154430107343 is a wasteful number, since it uses less digits than its factorization.
56154430107343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 244857.
The product of its (nonzero) digits is 1814400, while the sum is 46.
The spelling of 56154430107343 in words is "fifty-six trillion, one hundred fifty-four billion, four hundred thirty million, one hundred seven thousand, three hundred forty-three".
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