Base | Representation |
---|---|
bin | 101000110111001101110… |
… | …1100010001101011101011 |
3 | 201212220020001120010100111 |
4 | 1101232123230101223223 |
5 | 1214003320342043430 |
6 | 15540003321315151 |
7 | 1116516021110320 |
oct | 121563354215353 |
9 | 21786201503314 |
10 | 5616134331115 |
11 | 1875875465900 |
12 | 768540035ab7 |
13 | 3197a357b959 |
14 | 155b72768b47 |
15 | 9b14dc6bc2a |
hex | 51b9bb11aeb |
5616134331115 has 48 divisors (see below), whose sum is σ = 8477528842944. Its totient is φ = 3496188706560.
The previous prime is 5616134331079. The next prime is 5616134331163. The reversal of 5616134331115 is 5111334316165.
It is not a de Polignac number, because 5616134331115 - 211 = 5616134329067 is a prime.
It is a super-3 number, since 3×56161343311153 (a number of 39 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2199669 + ... + 4008841.
It is an arithmetic number, because the mean of its divisors is an integer number (176615184228).
Almost surely, 25616134331115 is an apocalyptic number.
5616134331115 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5616134331115 is a deficient number, since it is larger than the sum of its proper divisors (2861394511829).
5616134331115 is a wasteful number, since it uses less digits than its factorization.
5616134331115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1809940 (or 1809929 counting only the distinct ones).
The product of its digits is 97200, while the sum is 40.
The spelling of 5616134331115 in words is "five trillion, six hundred sixteen billion, one hundred thirty-four million, three hundred thirty-one thousand, one hundred fifteen".
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