Base | Representation |
---|---|
bin | 10000010110001000110… |
… | …00111010010010001011 |
3 | 1222200200200220021221022 |
4 | 20023010120322102023 |
5 | 33200214444104003 |
6 | 1110003015303055 |
7 | 55401656304341 |
oct | 10130430722213 |
9 | 1880620807838 |
10 | 561640613003 |
11 | 1a7210536378 |
12 | 90a2437aa8b |
13 | 40c68760592 |
14 | 1d27d93d991 |
15 | e922408738 |
hex | 82c463a48b |
561640613003 has 4 divisors (see below), whose sum is σ = 561690278688. Its totient is φ = 561590947320.
The previous prime is 561640612993. The next prime is 561640613029. The reversal of 561640613003 is 300316046165.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300316046165 = 5 ⋅60063209233.
It is a cyclic number.
It is not a de Polignac number, because 561640613003 - 220 = 561639564427 is a prime.
It is a super-2 number, since 2×5616406130032 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (561640613603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24815876 + ... + 24838497.
It is an arithmetic number, because the mean of its divisors is an integer number (140422569672).
Almost surely, 2561640613003 is an apocalyptic number.
561640613003 is a deficient number, since it is larger than the sum of its proper divisors (49665685).
561640613003 is a wasteful number, since it uses less digits than its factorization.
561640613003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49665684.
The product of its (nonzero) digits is 38880, while the sum is 35.
Adding to 561640613003 its reverse (300316046165), we get a palindrome (861956659168).
The spelling of 561640613003 in words is "five hundred sixty-one billion, six hundred forty million, six hundred thirteen thousand, three".
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