Base | Representation |
---|---|
bin | 11001100100111001111000… |
… | …11010001111011100111001 |
3 | 21101010211120220100220021020 |
4 | 30302130330122033130321 |
5 | 24332443403211044423 |
6 | 315341542521333053 |
7 | 14563316044054353 |
oct | 1462347432173471 |
9 | 241124526326236 |
10 | 56243610253113 |
11 | 16a148657a1338 |
12 | 638447b337189 |
13 | 254c9990b442a |
14 | dc62c33440d3 |
15 | 67805a98d4e3 |
hex | 33273c68f739 |
56243610253113 has 16 divisors (see below), whose sum is σ = 78399903880320. Its totient is φ = 35865490572912.
The previous prime is 56243610253111. The next prime is 56243610253121. The reversal of 56243610253113 is 31135201634265.
It is a happy number.
It is not a de Polignac number, because 56243610253113 - 21 = 56243610253111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (56243610253111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 770402806 + ... + 770475807.
It is an arithmetic number, because the mean of its divisors is an integer number (4899993992520).
Almost surely, 256243610253113 is an apocalyptic number.
It is an amenable number.
56243610253113 is a deficient number, since it is larger than the sum of its proper divisors (22156293627207).
56243610253113 is an equidigital number, since it uses as much as digits as its factorization.
56243610253113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1540878685 (or 1540878639 counting only the distinct ones).
The product of its (nonzero) digits is 388800, while the sum is 42.
Adding to 56243610253113 its reverse (31135201634265), we get a palindrome (87378811887378).
The spelling of 56243610253113 in words is "fifty-six trillion, two hundred forty-three billion, six hundred ten million, two hundred fifty-three thousand, one hundred thirteen".
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