Base | Representation |
---|---|
bin | 110100011001100101… |
… | …001111111110111111 |
3 | 12101020010012122210002 |
4 | 310121211033332333 |
5 | 1410212011120142 |
6 | 41502555504515 |
7 | 4031161104002 |
oct | 643145177677 |
9 | 171203178702 |
10 | 56263770047 |
11 | 21952482211 |
12 | aaa275813b |
13 | 53c868ca34 |
14 | 2a1a5a1539 |
15 | 16e4731a32 |
hex | d1994ffbf |
56263770047 has 2 divisors, whose sum is σ = 56263770048. Its totient is φ = 56263770046.
The previous prime is 56263770037. The next prime is 56263770103. The reversal of 56263770047 is 74007736265.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56263770047 - 218 = 56263507903 is a prime.
It is a super-2 number, since 2×562637700472 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 56263769983 and 56263770010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56263770037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28131885023 + 28131885024.
It is an arithmetic number, because the mean of its divisors is an integer number (28131885024).
Almost surely, 256263770047 is an apocalyptic number.
56263770047 is a deficient number, since it is larger than the sum of its proper divisors (1).
56263770047 is an equidigital number, since it uses as much as digits as its factorization.
56263770047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1481760, while the sum is 47.
The spelling of 56263770047 in words is "fifty-six billion, two hundred sixty-three million, seven hundred seventy thousand, forty-seven".
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