Base | Representation |
---|---|
bin | 11001100110100011010010… |
… | …11111010001010011010111 |
3 | 21101100020122211001211220111 |
4 | 30303101221133101103113 |
5 | 24334410302441332413 |
6 | 315423542204143451 |
7 | 14600361316361341 |
oct | 1463215137212327 |
9 | 241306584054814 |
10 | 56300201120983 |
11 | 16a36865875a26 |
12 | 6393433537b87 |
13 | 255511746bc71 |
14 | dc8d31130291 |
15 | 67976dc82d3d |
hex | 3334697d14d7 |
56300201120983 has 2 divisors, whose sum is σ = 56300201120984. Its totient is φ = 56300201120982.
The previous prime is 56300201120909. The next prime is 56300201121011. The reversal of 56300201120983 is 38902110200365.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56300201120983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56300201123983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28150100560491 + 28150100560492.
It is an arithmetic number, because the mean of its divisors is an integer number (28150100560492).
Almost surely, 256300201120983 is an apocalyptic number.
56300201120983 is a deficient number, since it is larger than the sum of its proper divisors (1).
56300201120983 is an equidigital number, since it uses as much as digits as its factorization.
56300201120983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 56300201120983 in words is "fifty-six trillion, three hundred billion, two hundred one million, one hundred twenty thousand, nine hundred eighty-three".
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