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5630540235113 is a prime number
BaseRepresentation
bin101000111101111011001…
…0110011100000101101001
3201221021102000210212112102
41101323312112130011221
51214222321300010423
615550345014023145
71120536015220403
oct121736626340551
921837360725472
105630540235113
1118809981a1792
1276b2a0647ab5
1331ac5acb84c1
1415673bb01b73
159b6e382cc28
hex51ef659c169

5630540235113 has 2 divisors, whose sum is σ = 5630540235114. Its totient is φ = 5630540235112.

The previous prime is 5630540235007. The next prime is 5630540235127. The reversal of 5630540235113 is 3115320450365.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3129739577449 + 2500800657664 = 1769107^2 + 1581392^2 .

It is a cyclic number.

It is not a de Polignac number, because 5630540235113 - 218 = 5630539972969 is a prime.

It is not a weakly prime, because it can be changed into another prime (5630540235143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2815270117556 + 2815270117557.

It is an arithmetic number, because the mean of its divisors is an integer number (2815270117557).

Almost surely, 25630540235113 is an apocalyptic number.

It is an amenable number.

5630540235113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5630540235113 is an equidigital number, since it uses as much as digits as its factorization.

5630540235113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 5630540235113 its reverse (3115320450365), we get a palindrome (8745860685478).

The spelling of 5630540235113 in words is "five trillion, six hundred thirty billion, five hundred forty million, two hundred thirty-five thousand, one hundred thirteen".