Base | Representation |
---|---|
bin | 101000111101111011001… |
… | …0110011100000101101001 |
3 | 201221021102000210212112102 |
4 | 1101323312112130011221 |
5 | 1214222321300010423 |
6 | 15550345014023145 |
7 | 1120536015220403 |
oct | 121736626340551 |
9 | 21837360725472 |
10 | 5630540235113 |
11 | 18809981a1792 |
12 | 76b2a0647ab5 |
13 | 31ac5acb84c1 |
14 | 15673bb01b73 |
15 | 9b6e382cc28 |
hex | 51ef659c169 |
5630540235113 has 2 divisors, whose sum is σ = 5630540235114. Its totient is φ = 5630540235112.
The previous prime is 5630540235007. The next prime is 5630540235127. The reversal of 5630540235113 is 3115320450365.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3129739577449 + 2500800657664 = 1769107^2 + 1581392^2 .
It is a cyclic number.
It is not a de Polignac number, because 5630540235113 - 218 = 5630539972969 is a prime.
It is not a weakly prime, because it can be changed into another prime (5630540235143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2815270117556 + 2815270117557.
It is an arithmetic number, because the mean of its divisors is an integer number (2815270117557).
Almost surely, 25630540235113 is an apocalyptic number.
It is an amenable number.
5630540235113 is a deficient number, since it is larger than the sum of its proper divisors (1).
5630540235113 is an equidigital number, since it uses as much as digits as its factorization.
5630540235113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 5630540235113 its reverse (3115320450365), we get a palindrome (8745860685478).
The spelling of 5630540235113 in words is "five trillion, six hundred thirty billion, five hundred forty million, two hundred thirty-five thousand, one hundred thirteen".
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