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56334441443213 is a prime number
BaseRepresentation
bin11001100111100011000100…
…10111101110111110001101
321101110112001002021102212002
430303301202113232332031
524340440414002140323
6315451403553122045
714603012655330563
oct1463614227567615
9241415032242762
1056334441443213
1116a4a33661689a
126399baa559325
13255841318a16b
14dca85c7a9a33
1567a5c4ca3828
hex333c625eef8d

56334441443213 has 2 divisors, whose sum is σ = 56334441443214. Its totient is φ = 56334441443212.

The previous prime is 56334441443209. The next prime is 56334441443237. The reversal of 56334441443213 is 31234414443365.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39050025996004 + 17284415447209 = 6249002^2 + 4157453^2 .

It is a cyclic number.

It is not a de Polignac number, because 56334441443213 - 22 = 56334441443209 is a prime.

It is a super-3 number, since 3×563344414432133 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56334441443513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28167220721606 + 28167220721607.

It is an arithmetic number, because the mean of its divisors is an integer number (28167220721607).

Almost surely, 256334441443213 is an apocalyptic number.

It is an amenable number.

56334441443213 is a deficient number, since it is larger than the sum of its proper divisors (1).

56334441443213 is an equidigital number, since it uses as much as digits as its factorization.

56334441443213 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4976640, while the sum is 47.

Adding to 56334441443213 its reverse (31234414443365), we get a palindrome (87568855886578).

The spelling of 56334441443213 in words is "fifty-six trillion, three hundred thirty-four billion, four hundred forty-one million, four hundred forty-three thousand, two hundred thirteen".