Base | Representation |
---|---|
bin | 101001000010011100100… |
… | …1100110010001101000011 |
3 | 201222012110211200000210112 |
4 | 1102010321030302031003 |
5 | 1214402213414243243 |
6 | 15555032412421535 |
7 | 1121331460344134 |
oct | 122047114621503 |
9 | 21865424600715 |
10 | 5640251712323 |
11 | 1885021061308 |
12 | 771150a778ab |
13 | 31bb47c95c17 |
14 | 156dbd7dbc8b |
15 | 9bab11e7818 |
hex | 52139332343 |
5640251712323 has 2 divisors, whose sum is σ = 5640251712324. Its totient is φ = 5640251712322.
The previous prime is 5640251712311. The next prime is 5640251712343. The reversal of 5640251712323 is 3232171520465.
5640251712323 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5640251712323 - 212 = 5640251708227 is a prime.
It is not a weakly prime, because it can be changed into another prime (5640251712343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2820125856161 + 2820125856162.
It is an arithmetic number, because the mean of its divisors is an integer number (2820125856162).
Almost surely, 25640251712323 is an apocalyptic number.
5640251712323 is a deficient number, since it is larger than the sum of its proper divisors (1).
5640251712323 is an equidigital number, since it uses as much as digits as its factorization.
5640251712323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 302400, while the sum is 41.
The spelling of 5640251712323 in words is "five trillion, six hundred forty billion, two hundred fifty-one million, seven hundred twelve thousand, three hundred twenty-three".
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