Base | Representation |
---|---|
bin | 101001000010011100100… |
… | …1100110010001100110111 |
3 | 201222012110211200000210002 |
4 | 1102010321030302030313 |
5 | 1214402213414243221 |
6 | 15555032412421515 |
7 | 1121331460344116 |
oct | 122047114621467 |
9 | 21865424600702 |
10 | 5640251712311 |
11 | 18850210612a7 |
12 | 771150a7789b |
13 | 31bb47c95c08 |
14 | 156dbd7dbc7d |
15 | 9bab11e780b |
hex | 52139332337 |
5640251712311 has 2 divisors, whose sum is σ = 5640251712312. Its totient is φ = 5640251712310.
The previous prime is 5640251712287. The next prime is 5640251712323. The reversal of 5640251712311 is 1132171520465.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5640251712311 - 210 = 5640251711287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5640251714311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2820125856155 + 2820125856156.
It is an arithmetic number, because the mean of its divisors is an integer number (2820125856156).
Almost surely, 25640251712311 is an apocalyptic number.
5640251712311 is a deficient number, since it is larger than the sum of its proper divisors (1).
5640251712311 is an equidigital number, since it uses as much as digits as its factorization.
5640251712311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 38.
The spelling of 5640251712311 in words is "five trillion, six hundred forty billion, two hundred fifty-one million, seven hundred twelve thousand, three hundred eleven".
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