Base | Representation |
---|---|
bin | 101001000010100001111… |
… | …1110011111001111011101 |
3 | 201222012221102212201002102 |
4 | 1102011003332133033131 |
5 | 1214403101210422023 |
6 | 15555102351534445 |
7 | 1121336114211563 |
oct | 122050376371735 |
9 | 21865842781072 |
10 | 5640432514013 |
11 | 18851041212a0 |
12 | 7711a152a425 |
13 | 31bb7658a97b |
14 | 156dd9823a33 |
15 | 9bac200d628 |
hex | 52143f9f3dd |
5640432514013 has 16 divisors (see below), whose sum is σ = 6388031079360. Its totient is φ = 4933231094400.
The previous prime is 5640432514001. The next prime is 5640432514039. The reversal of 5640432514013 is 3104152340465.
It is a cyclic number.
It is not a de Polignac number, because 5640432514013 - 24 = 5640432513997 is a prime.
It is a super-2 number, since 2×56404325140132 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5640432513013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31372295 + ... + 31551572.
It is an arithmetic number, because the mean of its divisors is an integer number (399251942460).
Almost surely, 25640432514013 is an apocalyptic number.
It is an amenable number.
5640432514013 is a deficient number, since it is larger than the sum of its proper divisors (747598565347).
5640432514013 is a wasteful number, since it uses less digits than its factorization.
5640432514013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62924188.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 5640432514013 its reverse (3104152340465), we get a palindrome (8744584854478).
The spelling of 5640432514013 in words is "five trillion, six hundred forty billion, four hundred thirty-two million, five hundred fourteen thousand, thirteen".
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