Base | Representation |
---|---|
bin | 110100100010001111… |
… | …010000110100111001 |
3 | 12101121020111011120101 |
4 | 310202033100310321 |
5 | 1411011201020043 |
6 | 41525224355401 |
7 | 4034603412442 |
oct | 644217206471 |
9 | 171536434511 |
10 | 56409001273 |
11 | 21a17457619 |
12 | ab23315b61 |
13 | 541c7ac181 |
14 | 2a319a82c9 |
15 | 170236d24d |
hex | d223d0d39 |
56409001273 has 2 divisors, whose sum is σ = 56409001274. Its totient is φ = 56409001272.
The previous prime is 56409001261. The next prime is 56409001283. The reversal of 56409001273 is 37210090465.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 54982277289 + 1426723984 = 234483^2 + 37772^2 .
It is a cyclic number.
It is not a de Polignac number, because 56409001273 - 221 = 56406904121 is a prime.
It is a super-3 number, since 3×564090012733 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (56409001223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28204500636 + 28204500637.
It is an arithmetic number, because the mean of its divisors is an integer number (28204500637).
Almost surely, 256409001273 is an apocalyptic number.
It is an amenable number.
56409001273 is a deficient number, since it is larger than the sum of its proper divisors (1).
56409001273 is an equidigital number, since it uses as much as digits as its factorization.
56409001273 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45360, while the sum is 37.
The spelling of 56409001273 in words is "fifty-six billion, four hundred nine million, one thousand, two hundred seventy-three".
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