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56420144504653 is a prime number
BaseRepresentation
bin11001101010000010101101…
…01010111101111101001101
321101202201020212201001101211
430311001112222331331031
524343341423443122103
6315555020115134421
714612135530331506
oct1465012652757515
9241681225631354
1056420144504653
1116a82715780396
1263b27282a4411
1325635209c2537
14dd0a6cb39bad
1567c93dca336d
hex335056abdf4d

56420144504653 has 2 divisors, whose sum is σ = 56420144504654. Its totient is φ = 56420144504652.

The previous prime is 56420144504593. The next prime is 56420144504749. The reversal of 56420144504653 is 35640544102465.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35780232428964 + 20639912075689 = 5981658^2 + 4543117^2 .

It is a cyclic number.

It is not a de Polignac number, because 56420144504653 - 217 = 56420144373581 is a prime.

It is a super-2 number, since 2×564201445046532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 56420144504597 and 56420144504606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56420144508653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28210072252326 + 28210072252327.

It is an arithmetic number, because the mean of its divisors is an integer number (28210072252327).

Almost surely, 256420144504653 is an apocalyptic number.

It is an amenable number.

56420144504653 is a deficient number, since it is larger than the sum of its proper divisors (1).

56420144504653 is an equidigital number, since it uses as much as digits as its factorization.

56420144504653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912000, while the sum is 49.

The spelling of 56420144504653 in words is "fifty-six trillion, four hundred twenty billion, one hundred forty-four million, five hundred four thousand, six hundred fifty-three".