Base | Representation |
---|---|
bin | 11001101010011010110110… |
… | …01100001001101100010111 |
3 | 21101210221201010120022112111 |
4 | 30311031123030021230113 |
5 | 24344044444413323411 |
6 | 320005002144131451 |
7 | 14613104645465014 |
oct | 1465153314115427 |
9 | 241727633508474 |
10 | 56433105214231 |
11 | 16a8816675a319 |
12 | 63b5144906b87 |
13 | 2564807bb8665 |
14 | dd153c19870b |
15 | 67ce4ba43721 |
hex | 33535b309b17 |
56433105214231 has 2 divisors, whose sum is σ = 56433105214232. Its totient is φ = 56433105214230.
The previous prime is 56433105214219. The next prime is 56433105214247. The reversal of 56433105214231 is 13241250133465.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56433105214231 - 225 = 56433071659799 is a prime.
It is a super-2 number, since 2×564331052142312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56433106214231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28216552607115 + 28216552607116.
It is an arithmetic number, because the mean of its divisors is an integer number (28216552607116).
Almost surely, 256433105214231 is an apocalyptic number.
56433105214231 is a deficient number, since it is larger than the sum of its proper divisors (1).
56433105214231 is an equidigital number, since it uses as much as digits as its factorization.
56433105214231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 40.
Adding to 56433105214231 its reverse (13241250133465), we get a palindrome (69674355347696).
The spelling of 56433105214231 in words is "fifty-six trillion, four hundred thirty-three billion, one hundred five million, two hundred fourteen thousand, two hundred thirty-one".
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