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56433105214231 is a prime number
BaseRepresentation
bin11001101010011010110110…
…01100001001101100010111
321101210221201010120022112111
430311031123030021230113
524344044444413323411
6320005002144131451
714613104645465014
oct1465153314115427
9241727633508474
1056433105214231
1116a8816675a319
1263b5144906b87
132564807bb8665
14dd153c19870b
1567ce4ba43721
hex33535b309b17

56433105214231 has 2 divisors, whose sum is σ = 56433105214232. Its totient is φ = 56433105214230.

The previous prime is 56433105214219. The next prime is 56433105214247. The reversal of 56433105214231 is 13241250133465.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 56433105214231 - 225 = 56433071659799 is a prime.

It is a super-2 number, since 2×564331052142312 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56433106214231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28216552607115 + 28216552607116.

It is an arithmetic number, because the mean of its divisors is an integer number (28216552607116).

Almost surely, 256433105214231 is an apocalyptic number.

56433105214231 is a deficient number, since it is larger than the sum of its proper divisors (1).

56433105214231 is an equidigital number, since it uses as much as digits as its factorization.

56433105214231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 56433105214231 its reverse (13241250133465), we get a palindrome (69674355347696).

The spelling of 56433105214231 in words is "fifty-six trillion, four hundred thirty-three billion, one hundred five million, two hundred fourteen thousand, two hundred thirty-one".