Base | Representation |
---|---|
bin | 101001000011111001010… |
… | …1110100100110011101111 |
3 | 201222111111202122200021011 |
4 | 1102013302232210303233 |
5 | 1214430102233332221 |
6 | 20000305323250051 |
7 | 1121501554360054 |
oct | 122076256446357 |
9 | 21874452580234 |
10 | 5643364355311 |
11 | 1886379069031 |
12 | 77187b379927 |
13 | 31c222ac97c7 |
14 | 1571d6d6702b |
15 | 9bbe45dc1e1 |
hex | 521f2ba4cef |
5643364355311 has 2 divisors, whose sum is σ = 5643364355312. Its totient is φ = 5643364355310.
The previous prime is 5643364355243. The next prime is 5643364355327. The reversal of 5643364355311 is 1135534633465.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5643364355311 - 27 = 5643364355183 is a prime.
It is a super-2 number, since 2×56433643553112 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5643364355351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2821682177655 + 2821682177656.
It is an arithmetic number, because the mean of its divisors is an integer number (2821682177656).
Almost surely, 25643364355311 is an apocalyptic number.
5643364355311 is a deficient number, since it is larger than the sum of its proper divisors (1).
5643364355311 is an equidigital number, since it uses as much as digits as its factorization.
5643364355311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5832000, while the sum is 49.
Adding to 5643364355311 its reverse (1135534633465), we get a palindrome (6778898988776).
The spelling of 5643364355311 in words is "five trillion, six hundred forty-three billion, three hundred sixty-four million, three hundred fifty-five thousand, three hundred eleven".
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