Base | Representation |
---|---|
bin | 101001000100000000000… |
… | …1110111110100111001111 |
3 | 201222112002120001001102211 |
4 | 1102020000032332213033 |
5 | 1214431033241002143 |
6 | 20000344020131251 |
7 | 1121510305414003 |
oct | 122100016764717 |
9 | 21875076031384 |
10 | 5643590953423 |
11 | 1886484a685a5 |
12 | 771923236b27 |
13 | 31c25aa37527 |
14 | 1572190b0703 |
15 | 9bc0944c49d |
hex | 522003be9cf |
5643590953423 has 2 divisors, whose sum is σ = 5643590953424. Its totient is φ = 5643590953422.
The previous prime is 5643590953411. The next prime is 5643590953543. The reversal of 5643590953423 is 3243590953465.
5643590953423 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5643590953423 - 25 = 5643590953391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5643590954423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2821795476711 + 2821795476712.
It is an arithmetic number, because the mean of its divisors is an integer number (2821795476712).
Almost surely, 25643590953423 is an apocalyptic number.
5643590953423 is a deficient number, since it is larger than the sum of its proper divisors (1).
5643590953423 is an equidigital number, since it uses as much as digits as its factorization.
5643590953423 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488000, while the sum is 58.
The spelling of 5643590953423 in words is "five trillion, six hundred forty-three billion, five hundred ninety million, nine hundred fifty-three thousand, four hundred twenty-three".
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