Base | Representation |
---|---|
bin | 110100100100001011… |
… | …110000111101001101 |
3 | 12101200111220022202012 |
4 | 310210023300331031 |
5 | 1411043024414413 |
6 | 41532352111005 |
7 | 4035451004414 |
oct | 644413607515 |
9 | 171614808665 |
10 | 56441638733 |
11 | 21a33919627 |
12 | ab32235465 |
13 | 542649878c |
14 | 2a3606247b |
15 | 17051687a8 |
hex | d242f0f4d |
56441638733 has 2 divisors, whose sum is σ = 56441638734. Its totient is φ = 56441638732.
The previous prime is 56441638723. The next prime is 56441638741. The reversal of 56441638733 is 33783614465.
56441638733 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 38226897289 + 18214741444 = 195517^2 + 134962^2 .
It is a cyclic number.
It is not a de Polignac number, because 56441638733 - 212 = 56441634637 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56441638723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28220819366 + 28220819367.
It is an arithmetic number, because the mean of its divisors is an integer number (28220819367).
Almost surely, 256441638733 is an apocalyptic number.
It is an amenable number.
56441638733 is a deficient number, since it is larger than the sum of its proper divisors (1).
56441638733 is an equidigital number, since it uses as much as digits as its factorization.
56441638733 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4354560, while the sum is 50.
The spelling of 56441638733 in words is "fifty-six billion, four hundred forty-one million, six hundred thirty-eight thousand, seven hundred thirty-three".
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