Base | Representation |
---|---|
bin | 11001101010111100101000… |
… | …10001010101011110010111 |
3 | 21101212200112011112021112022 |
4 | 30311132110101111132113 |
5 | 24344344121120244303 |
6 | 320021202022243355 |
7 | 14614316264110463 |
oct | 1465362421253627 |
9 | 241780464467468 |
10 | 56451242743703 |
11 | 16a949239366a5 |
12 | 63b8766b8655b |
13 | 256643876c912 |
14 | dd237cd854a3 |
15 | 67d65e016438 |
hex | 335794455797 |
56451242743703 has 2 divisors, whose sum is σ = 56451242743704. Its totient is φ = 56451242743702.
The previous prime is 56451242743697. The next prime is 56451242743723. The reversal of 56451242743703 is 30734724215465.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 56451242743703 - 218 = 56451242481559 is a prime.
It is a super-2 number, since 2×564512427437032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56451242743723) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28225621371851 + 28225621371852.
It is an arithmetic number, because the mean of its divisors is an integer number (28225621371852).
Almost surely, 256451242743703 is an apocalyptic number.
56451242743703 is a deficient number, since it is larger than the sum of its proper divisors (1).
56451242743703 is an equidigital number, since it uses as much as digits as its factorization.
56451242743703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16934400, while the sum is 53.
The spelling of 56451242743703 in words is "fifty-six trillion, four hundred fifty-one billion, two hundred forty-two million, seven hundred forty-three thousand, seven hundred three".
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