Base | Representation |
---|---|
bin | 11001101100011010101111… |
… | …11101110111011100010111 |
3 | 21102001111221112122001211022 |
4 | 30312031113331313130113 |
5 | 24401211111234131201 |
6 | 320100315522031355 |
7 | 14621055355660343 |
oct | 1466152775673427 |
9 | 242044845561738 |
10 | 56501770614551 |
11 | 170042a2571949 |
12 | 64065087a855b |
13 | 256b12b9a2552 |
14 | dd49b3844623 |
15 | 67eb19dcc41b |
hex | 336357f77717 |
56501770614551 has 4 divisors (see below), whose sum is σ = 56653249892712. Its totient is φ = 56350291336392.
The previous prime is 56501770614511. The next prime is 56501770614557. The reversal of 56501770614551 is 15541607710565.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 56501770614551 - 210 = 56501770613527 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 56501770614493 and 56501770614502.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (56501770614557) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75739638521 + ... + 75739639266.
It is an arithmetic number, because the mean of its divisors is an integer number (14163312473178).
Almost surely, 256501770614551 is an apocalyptic number.
56501770614551 is a deficient number, since it is larger than the sum of its proper divisors (151479278161).
56501770614551 is a wasteful number, since it uses less digits than its factorization.
56501770614551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151479278160.
The product of its (nonzero) digits is 4410000, while the sum is 53.
The spelling of 56501770614551 in words is "fifty-six trillion, five hundred one billion, seven hundred seventy million, six hundred fourteen thousand, five hundred fifty-one".
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