Base | Representation |
---|---|
bin | 11001101100110000100011… |
… | …01110010111010010110101 |
3 | 21102002122011101100110212011 |
4 | 30312120101232113102311 |
5 | 24401404100111004402 |
6 | 320105533303324221 |
7 | 14621651434006402 |
oct | 1466302156272265 |
9 | 242078141313764 |
10 | 56513477047477 |
11 | 1700925a5431aa |
12 | 6408835150671 |
13 | 256c27607c338 |
14 | dd53a44852a9 |
15 | 6800a29aeed7 |
hex | 336611b974b5 |
56513477047477 has 2 divisors, whose sum is σ = 56513477047478. Its totient is φ = 56513477047476.
The previous prime is 56513477047463. The next prime is 56513477047481. The reversal of 56513477047477 is 77474077431565.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33792991954276 + 22720485093201 = 5813174^2 + 4766601^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-56513477047477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (56513477047457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28256738523738 + 28256738523739.
It is an arithmetic number, because the mean of its divisors is an integer number (28256738523739).
Almost surely, 256513477047477 is an apocalyptic number.
It is an amenable number.
56513477047477 is a deficient number, since it is larger than the sum of its proper divisors (1).
56513477047477 is an equidigital number, since it uses as much as digits as its factorization.
56513477047477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 484041600, while the sum is 67.
The spelling of 56513477047477 in words is "fifty-six trillion, five hundred thirteen billion, four hundred seventy-seven million, forty-seven thousand, four hundred seventy-seven".
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