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56531511513437 is a prime number
BaseRepresentation
bin11001101101010010001001…
…01010011001000101011101
321102011100201020101021021212
430312221010222121011131
524402203013421412222
6320122115020434205
714623160361310352
oct1466510452310535
9242140636337255
1056531511513437
1117015974526424
1264102289a8965
132570b8b48957c
14dd61d56c4629
156807aadc56e2
hex336a44a9915d

56531511513437 has 2 divisors, whose sum is σ = 56531511513438. Its totient is φ = 56531511513436.

The previous prime is 56531511513403. The next prime is 56531511513469. The reversal of 56531511513437 is 73431511513565.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 54786732061636 + 1744779451801 = 7401806^2 + 1320901^2 .

It is a cyclic number.

It is not a de Polignac number, because 56531511513437 - 220 = 56531510464861 is a prime.

It is a super-3 number, since 3×565315115134373 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (56531511513637) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28265755756718 + 28265755756719.

It is an arithmetic number, because the mean of its divisors is an integer number (28265755756719).

Almost surely, 256531511513437 is an apocalyptic number.

It is an amenable number.

56531511513437 is a deficient number, since it is larger than the sum of its proper divisors (1).

56531511513437 is an equidigital number, since it uses as much as digits as its factorization.

56531511513437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2835000, while the sum is 50.

The spelling of 56531511513437 in words is "fifty-six trillion, five hundred thirty-one billion, five hundred eleven million, five hundred thirteen thousand, four hundred thirty-seven".